Distance-transitive digraphs are Seymour-tight
Prove that every distance-transitive digraph is a Seymour-tight orientation; that is, for every vertex v the sizes of the first and second out-neighbourhoods are equal.
References
We conjecture the following. Every distance transitive digraph is a Seymour-tight orientation.
— Seymour-tight orientations
(2603.29626 - Guo et al., 31 Mar 2026) in Discussion (Concluding section)