Crowded spaces with nowhere dense tightness: resolvability
Determine whether every crowded topological space X that has nowhere dense tightness—meaning that for every subset A ⊆ X and every point x that is an accumulation point of A, there exists a subset N ⊆ A such that N is nowhere dense in X and x is an accumulation point of N—is resolvable (i.e., contains two disjoint dense subsets).
References
However, the following question remains open.
Question 1.4. Is every crowded space with NDT resolvable?
— On resolvability and tightness in uncountable spaces
(2402.11213 - Lipin, 17 Feb 2024) in Question 1.4, Section 1 (Introduction)