Classify cube complex groups with all infinite-index subgroups free
Determine whether for every compact, non-positively curved cube complex X in which every subgroup of infinite index in π1(X) is free, the group π1(X) must be either a free group or a surface group.
References
This final section contains some open questions that are suggested by the results of this paper.
Question 6.2. Let X be a compact, non-positively curved cube complex with every subgroup of infinite index free. Must π 1X) be either a free group or a surface group?
                — Surface groups among cubulated hyperbolic and one-relator groups
                
                (2406.02121 - Wilton, 4 Jun 2024) in Section 6, Question 6.2