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Classify cube complex groups with all infinite-index subgroups free

Determine whether for every compact, non-positively curved cube complex X in which every subgroup of infinite index in π1(X) is free, the group π1(X) must be either a free group or a surface group.

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Background

The main theorem uses separability of hyperplane stabilizers (via virtual specialness) to conclude the existence of one-ended quasiconvex subgroups unless the group is free or a surface group. Removing the virtual specialness/separability assumption would require new methods.

The author notes that combining Theorem A with the flat-closing conjecture would imply a positive answer, but the question remains open without these hypotheses.

References

This final section contains some open questions that are suggested by the results of this paper.

Question 6.2. Let X be a compact, non-positively curved cube complex with every subgroup of infinite index free. Must π 1X) be either a free group or a surface group?

Surface groups among cubulated hyperbolic and one-relator groups (2406.02121 - Wilton, 4 Jun 2024) in Section 6, Question 6.2