Automaticity of anti-k-nacci deviations
Prove that for every integer k, if X_n denotes the sequence obtained by summing k consecutive missing numbers in the corresponding greedy mex construction, then the difference X_n-(k^2+1)n is k-automatic.
References
We define the anti-$k$-naccis as the sums of $k$ consecutive missing numbers. There is an obvious pattern. \begin{conjecture}[The Clergyman's Conjecture.] Let $X_n$ be the sequence of anti-$k$-naccis. The difference $ X_n-(k2+1)n $ is $k$-automatic.
— Using Walnut to solve problems from the OEIS
(2503.04122 - Bosma et al., 6 Mar 2025) in Section 3, Conjecture (The Clergyman’s Conjecture)