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Combinatorially Determined Zeroes of Bernstein--Sato Ideals for Tame and Free Arrangements (1909.00547v3)

Published 2 Sep 2019 in math.AG, math.AC, and math.CV

Abstract: For a central, not necessarily reduced, hyperplane arrangement $f$ equipped with any factorization $f = f_{1} \cdots f_{r}$ and for $f{\prime}$ dividing $f$, we consider a more general type of Bernstein--Sato ideal consisting of the polynomials $B(S) \in \mathbb{C}[s_{1}, \dots, s_{r}]$ satisfying the functional equation $B(S) f{\prime} f_{1}{s_{1}} \cdots f_{r}{s_{r}} \in \text{A}{n}(\mathbb{C})[s{1}, \dots, s_{r}] f_{1}{s_{1} + 1} \cdots f_{r}{s_{r} + 1}.$ Generalizing techniques due to Maisonobe, we compute the zero locus of the standard Bernstein--Sato ideal in the sense of Budur (i.e. $f{\prime} = 1)$ for any factorization of a free and reduced $f$ and for certain factorizations of a non-reduced $f$. We also compute the roots of the Bernstein--Sato polynomial for any power of a free and reduced arrangement. If $f$ is tame, we give a combinatorial formula for the roots lying in $[-1,0).$ For $f{\prime} \neq 1$ and any factorization of a line arrangement, we compute the zero locus of this ideal. For free and reduced arrangements of larger rank, we compute the zero locus provided $\text{deg}(f{\prime}) \leq 4$ and give good estimates otherwise. Along the way we generalize a duality formula for $\mathscr{D}{X,\mathfrak{x}}[S]f{\prime}f{1}{s_{1}} \cdots f_{r}{s_{r}}$ that was first proved by Narv\'aez-Macarro for $f$ reduced, $f{\prime} = 1$, and $r = 1.$ As an application, we investigate the minimum number of hyperplanes one must add to a tame $f$ so that the resulting arrangement is free. This notion of freeing a divisor has been explicitly studied by Mond and Schulze, albeit not for hyperplane arrangements. We show that small roots of the Bernstein--Sato polynomial of $f$ can force lower bounds for this number.

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