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Hardy's inequality and curvature

Published 12 Jan 2011 in math.SP, math-ph, math.FA, and math.MP | (1101.2331v2)

Abstract: A Hardy inequality of the form [\int_{\tilde{\Omega}} |\nabla f({\bf{x}})|p d {\bf{x}} \ge (\frac{p-1}{p})p \int_{\tilde{\Omega}} {1 + a(\delta, \partial \tilde{\Omega})(\x)}\frac{|f({\bf{x}})|p}{\delta({\bf{x}})p} d{\bf{x}}, ] for all $f \in C_0{\infty}({\tilde{\Omega}})$, is considered for $p\in (1,\infty)$, where ${\tilde{\Omega}}$ can be either $\Omega$ or $\mathbb{R}n \setminus \Omega$ with $\Omega$ a domain in $\mathbb{R}n$, $n \ge 2$, and $\delta({\bf{x}})$ is the distance from ${\bf{x}} \in {\tilde{\Omega}} $ to the boundary $ \partial {\tilde{\Omega}}.$ The main emphasis is on determining the dependance of $a(\delta, \partial {\tilde{\Omega}})$ on the geometric properties of $\partial {\tilde{\Omega}}.$ A Hardy inequality is also established for any doubly connected domain $\Omega$ in $\mathbb{R}2$ in terms of a uniformisation of $\Omega,$ that is, any conformal univalent map of $\Omega$ onto an annulus.

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