Papers
Topics
Authors
Recent
Detailed Answer
Quick Answer
Concise responses based on abstracts only
Detailed Answer
Well-researched responses based on abstracts and relevant paper content.
Custom Instructions Pro
Preferences or requirements that you'd like Emergent Mind to consider when generating responses
Gemini 2.5 Flash
Gemini 2.5 Flash 84 tok/s
Gemini 2.5 Pro 45 tok/s Pro
GPT-5 Medium 28 tok/s Pro
GPT-5 High 21 tok/s Pro
GPT-4o 92 tok/s Pro
GPT OSS 120B 425 tok/s Pro
Kimi K2 157 tok/s Pro
2000 character limit reached

On the number of gaps of sequences with Poissonian Pair Correlations (1908.06292v1)

Published 17 Aug 2019 in math.NT and math.CA

Abstract: A sequence $(x_n)$ on the torus is said to have Poissonian pair correlations if $# {1\le i\neq j\le N: |x_i-x_j| \le s/N}=2sN(1+o(1))$ for all reals $s>0$, as $N\to \infty$. It is known that, if $(x_n)$ has Poissonian pair correlations, then the number $g(n)$ of different gap lengths between neighboring elements of ${x_1,\ldots,x_n}$ cannot be bounded along every index subsequence $(n_t)$. First, we improve this by showing that the maximum among the multiplicities of the neighboring gap lengths of ${x_1,\ldots,x_n}$ is $o(n)$, as $n\to \infty$. Furthermore, we show that, for every function $f: \mathbf{N}+\to \mathbf{N}+$ with $\lim_n f(n)=\infty$, there exists a sequence $(x_n)$ with Poissonian pair correlations and such that $g(n) \le f(n)$ for all sufficiently large $n$. This answers negatively a question posed by G. Larcher.

List To Do Tasks Checklist Streamline Icon: https://streamlinehq.com

Collections

Sign up for free to add this paper to one or more collections.

Summary

We haven't generated a summary for this paper yet.

Ai Generate Text Spark Streamline Icon: https://streamlinehq.com

Paper Prompts

Sign up for free to create and run prompts on this paper using GPT-5.

Dice Question Streamline Icon: https://streamlinehq.com

Follow-up Questions

We haven't generated follow-up questions for this paper yet.