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Large Subsets of $\mathbb{Z}_m^n$ without Arithmetic Progressions (2211.02588v1)

Published 4 Nov 2022 in math.NT and math.CO

Abstract: For integers $m$ and $n$, we study the problem of finding good lower bounds for the size of progression-free sets in $(\mathbb{Z}{m}{n},+)$. Let $r{k}(\mathbb{Z}{m}{n})$ denote the maximal size of a subset of $\mathbb{Z}{m}{n}$ without arithmetic progressions of length $k$ and let $P{-}(m)$ denote the least prime factor of $m$. We construct explicit progression-free sets and obtain the following improved lower bounds for $r_{k}(\mathbb{Z}{m}{n})$: If $k\geq 5$ is odd and $P{-}(m)\geq (k+2)/2$, then [r_k(\mathbb{Z}_mn) \gg{m,k} \frac{\bigl\lfloor \frac{k-1}{k+1}m +1\bigr\rfloor{n}}{n{\lfloor \frac{k-1}{k+1}m \rfloor/2}}. ] If $k\geq 4$ is even, $P{-}(m) \geq k$ and $m \equiv -1 \bmod k$, then [r_{k}(\mathbb{Z}{m}{n}) \gg{m,k} \frac{\bigl\lfloor \frac{k-2}{k}m + 2\bigr\rfloor{n}}{n{\lfloor \frac{k-2}{k}m + 1\rfloor/2}}.] Moreover, we give some further improved lower bounds on $r_k(\mathbb{Z}_pn)$ for primes $p \leq 31$ and progression lengths $4 \leq k \leq 8$.

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