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The Complexity of Drawing Graphs on Few Lines and Few Planes

Published 21 Jul 2016 in cs.CC and cs.CG | (1607.06444v4)

Abstract: It is well known that any graph admits a crossing-free straight-line drawing in $\mathbb{R}3$ and that any planar graph admits the same even in $\mathbb{R}2$. For a graph $G$ and $d \in {2,3}$, let $\rho1_d(G)$ denote the smallest number of lines in $\mathbb{R}d$ whose union contains a crossing-free straight-line drawing of $G$. For $d=2$, $G$ must be planar. Similarly, let $\rho2_3(G)$ denote the smallest number of planes in $\mathbb{R}3$ whose union contains a crossing-free straight-line drawing of $G$. We investigate the complexity of computing these three parameters and obtain the following hardness and algorithmic results. - For $d\in{2,3}$, we prove that deciding whether $\rho1_d(G)\le k$ for a given graph $G$ and integer $k$ is ${\exists\mathbb{R}}$-complete. - Since $\mathrm{NP}\subseteq{\exists\mathbb{R}}$, deciding $\rho1_d(G)\le k$ is NP-hard for $d\in{2,3}$. On the positive side, we show that the problem is fixed-parameter tractable with respect to $k$. - Since ${\exists\mathbb{R}}\subseteq\mathrm{PSPACE}$, both $\rho1_2(G)$ and $\rho1_3(G)$ are computable in polynomial space. On the negative side, we show that drawings that are optimal with respect to $\rho1_2$ or $\rho1_3$ sometimes require irrational coordinates. - We prove that deciding whether $\rho2_3(G)\le k$ is NP-hard for any fixed $k \ge 2$. Hence, the problem is not fixed-parameter tractable with respect to $k$ unless $\mathrm{P}=\mathrm{NP}$.

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