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A note on Itoh (e)-Valuation Rings of and Ideal (1607.05341v1)

Published 18 Jul 2016 in math.AC

Abstract: Let $I$ be a regular proper ideal in a Noetherian ring $R$, let $e \ge 2$ be an integer, let $\mathbf T_e = R[u,tI,u{\frac{1}{e}}]' \cap R[u{\frac{1}{e}},t{\frac{1}{e}}]$ (where $t$ is an indeterminate and $u =\frac{1}{t}$), and let $\mathbf r_e = u{\frac{1}{e}} \mathbf T_e$. Then the Itoh (e)-valuation rings of $I$ are the rings $(\mathbf T_e/z){(p/z)}$, where $p$ varies over the (height one) associated prime ideals of $\mathbf r_e$ and $z$ is the (unique) minimal prime ideal in $\mathbf T_e$ that is contained in $p$. We show, among other things: (1) $\mathbf r_e$ is a radical ideal if and only if $e$ is a common multiple of the Rees integers of $I$. (2) For each integer $k \ge 2$, there is a one-to-one correspondence between the Itoh (k)-valuation rings $(V,N^)$ of $I$ and the Rees valuation rings $(W,Q)$ of $uR[u,tI]$; namely, if $F(u)$ is the quotient field of $W$, then $V*$ is the integral closure of $W$ in $F(u{\frac{1}{k}})$. (3) For each integer $k \ge 2$, if $(V,N^)$ and $(W,Q)$ are corresponding valuation rings, as in (2), then $V*$ is a finite integral extension domain of $W$, and $W$ and $V*$ satisfy the Fundamental Equality with no splitting. Also, if $uW = Qe$, and if the greatest common divisor of $e$ and $k$ is $d$, and $c$ is the integer such that $cd = k$, then $QV* = {N*}c$ and $[(V/N^):(W/Q)] = d$. Further, if $uW = Qe$ and $k = qe$ is a multiple of $e$, then there exists a unit $\theta{e} \in V*$ such that $V* = W[\theta_{e},u{\frac{1}{k}}]$ is a finite free integral extension domain of $W, QV* = {N*}q, N* = u{\frac{1}{k}}V*$, and $[V*:W] = k$. (4) If the Rees integers of $I$ are all equal to $e$, then $V* = W[\theta_e]$ is a simple free integral extension domain of $W, QV* = N* = u{\frac{1}{e}}V*$, and $[V*:W] = e = [(V/N^):(W/Q)]$.

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