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The sum-capture problem for abelian groups (1309.5582v2)

Published 22 Sep 2013 in cs.DM and math.CO

Abstract: Let $G$ be a finite abelian group, let $0 < \alpha < 1$, and let $A \subseteq G$ be a random set of size $|G|\alpha$. We let $$ \mu(A) = \max_{B,C:|B|=|C|=|A|}|{(a,b,c) \in A \times B \times C : a = b + c }|. $$ The issue is to determine upper bounds on $\mu(A)$ that hold with high probability over the random choice of $A$. Mennink and Preneel \cite{BM} conjecture that $\mu(A)$ should be close to $|A|$ (up to possible logarithmic factors in $|G|$) for $\alpha \leq 1/2$ and that $\mu(A)$ should not much exceed $|A|{3/2}$ for $\alpha \leq 2/3$. We prove the second half of this conjecture by showing that $$ \mu(A) \leq |A|3/|G| + 4|A|{3/2}\ln(|G|){1/2} $$ with high probability, for all $0 < \alpha < 1$. We note that $3\alpha - 1 \leq (3/2)\alpha$ for $\alpha \leq 2/3$. In previous work, Alon et al$.$ have shown that $\mu(A) \leq O(1)|A|3/|G|$ with high probability for $\alpha \geq 2/3$ while Kiltz, Pietrzak and Szegedy show that $\mu(A) \leq |A|{1 + 2\alpha}$ with high probability for $\alpha \leq 1/4$. Current bounds on $\mu(A)$ are essentially sharp for the range $2/3 \leq \alpha \leq 1$. Finding better bounds remains an open problem for the range $0 < \alpha < 2/3$ and especially for the range $1/4 < \alpha < 2/3$ in which the bound of Kiltz et al$.$ doesn't improve on the bound given in this paper (even if that bound applied). Moreover the conjecture of Mennink and Preneel for $\alpha \leq 1/2$ remains open.

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